X^2+14x=161.25=0

Solution for X^2+14x=161.25=0 equation:

X^2+14X=161.25=0

We move all terms to the left:

X^2+14X-(161.25)=0

We add all the numbers together, and all the variables

X^2+14X-161.25=0

a = 1; b = 14; c = -161.25;
Δ = b2-4ac
Δ = 142-4·1·(-161.25)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-29}{2*1}=\frac{-43}{2}
=-21+1/2
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+29}{2*1}=\frac{15}{2}
=7+1/2
$